result to a source 2003-04-09 - By Foxy Shadis
Result result = new StreamResult(new StringWriter());
...
Source source = new StreamSource(new
StringReader(result.getWriter().toString()));
--
Let me know if anything along those lines helps. I have no idea what kind of
buffering StringWriter uses, so you may want to wrap it in a buffered
writer.
My preferred method is this:
--
StringWriter result = new StringWriter();
...
transformer.transform(xmlSource, new StreamResult(result));
...
Source source = new StreamSource(new StringReader(result.toString()));
--
Which is roughly equivalent but easier for me to work with.
Swiftpaw Foxyshadis, wildlife artist
foxyshadis@(protected) | http://foxyshadis.dyndns.org/
>From: Simon Kitching <simon@(protected)>
>
>I expect that you could use a DOMResult, then get the root node of the
>resulting DOM, and wrap a DOMSource around it:
>
>DOMResult result = new DOMResult();
>transformer.transform(source, result);
>
>return new DOMSource(result.getNode());
>
>
>On Wed, 2003-04-09 at 22:44, Andrew Welch wrote:
> > Hi,
> >
> > Sorry if this is a faq...
> >
> > I have a custom uri resolver that I want to do a transform before
>passing the result back to the requesting stylesheet. How do I go from a
>result to a source? I can write the result out and then read it back in,
>says as a string or bytes, but this seems unecessary... my knowledge of
>streams is really lacking :(
> >
> > code sample:
> >
> > public Source resolve(String href, String base) throws
>TransformerException {
> > try {
> > URL context = new URL("file:///");
> > URL u = new URL(context, href);
> >
> > InputStream is = new FileInputStream(u.toString());
> >
> > TransformerFactory tf = TransformerFactory.newInstance();
> > Source xsl = new StreamSource(new
>File("C:\\test\\AddElementIdToStylesheet.xsl"));
> >
> > Result result = new StreamResult(???);
> > ^^^what type of result do I need here?
> >
> > Transformer transformer = tf.newTransformer(xsl);
> > transformer.transform(new StreamSource(is, u.toString()), result);
> >
> > return ????;
> > ^^^how do I return the result as a source?
> > } catch (Exception ex) {
> > System.out.println(ex.toString());
> > ex.printStackTrace();
> > }
> > return null;
> > }
> >
> > cheers
> > andrew
> >
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