xslt servlet trouble - nothing outputs 2003-03-28 - By Christine Li
It is cause of Sun JDK has a bundle of old version Xalan. Copying the new
xalan.jar to the %Tomcat_Home%/common/endorsed will solve this problem.
Christine Li
XSLT Development
IBM Toronto Lab
Tel: (905)413-2601
Email: jycli@(protected)
Ali Zain
Banatwala To: Christine Li <jycli@(protected)
.ibm.com>
<azb33@(protected)> cc: xalan-j-users@(protected)
.apache.org
Subject: Re: xslt servlet
trouble - nothing outputs
03/28/2003 01:27
PM
Hi Christine,
thanks for your help. By now I'm getting some
output, and at least it's the same error msg on both
windows and linux.
error msg:
The output format must have a
'{http://xml.apache.org/xslt}content-handler'
property!
any ideas? thanks....
--- Christine Li <jycli@(protected)> wrote:
> Do you get any error message, for example can't find
> the xsl or xml files?
> I don't see anything wrong in the servlet code that
> you provided. Can you
> try the sample servlet codes(from Xalan.2.5.D1
> release) with Tomcat? And
> also try your xml and xsl files without using
> servlet, just make sure they
> are right.
>
> Christine Li
> XSLT Development
> IBM Toronto Lab
> Tel: (905)413-2601
> Email: jycli@(protected)
>
>
>
>
>
> Ali Zain
>
>
> Banatwala To:
> xalan-j-users@(protected)
>
> <azb33@(protected)> cc:
>
>
>
> Subject: xslt servlet trouble - nothing outputs
>
> 03/25/2003 08:26
>
>
> PM
>
>
>
>
>
>
>
>
>
>
>
> Hi,
> i'm using Tomcat 4.1 and i'm having trouble trying
> to get my xml file to output in my servlet.
>
> i've tried it with JDOM and without. using File and
> URL as the StreamSource param, but nothing shows up.
> there's no output.
>
> both "movies.xml" and "movies.xsl" are in my
> servlet
> context root.
>
> somebody pls help!!
> thanx...
>
>
> here's my code:
> res.setContentType("text/html");
> PrintWriter out = res.getWriter();
>
> out.println("<html><head><title>Movie
> List</title></head><body>");
> out.println("<center><h1>Movie
> List</h1></center><br/>");
>
>
> Source inXsl = new StreamSource(new
>
URL("file","",getServletContext()+"movies.xsl").openStream());
> Source inXml = new StreamSource(new
>
URL("file","",getServletContext()+"movies.xml").openStream());
>
> TransformerFactory transFact =
> TransformerFactory.newInstance();
> Transformer trans =
> transFact.newTransformer(inXsl);
>
> trans.transform(inXml, new StreamResult(out));
>
> out.println("<body></html>");
>
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