xslt parameters not expanded 2007-03-29 - By misu200
Matthijs Wensveen-2 wrote:
>
> misu200 wrote:
>> Hello all,
>>
>> I have an XSLT parameter like:
>> <xsl:param name="DateFormat">'eeee'</xsl:param>
>>
>> I'm trying to use this XSLT parameter as a parameter to my custom class
>>
>> <xsl:value-of
>>
>> select="java:x.y.z.convertDate(string(calculationPeriodDates/terminationDate
/unadjustedDate),$DateFormat)"
>> />
>>
>> But each time I've found out that in z.convertDate the second parameter i
>> received is '$DateFormat'
>>
>> Why is that not 'eeee' (or whatever)?
>>
>> I've also tried somenthing like {$DateFormat} or string($DateFormat) but
>> it
>> doesn't work.
>>
>> Thanks,
>> Valentin
>>
>>
>
> Have you tried just outputting the param to the result, instead of
> passing it to a function? Does that work? Have you tried <xsl:param
> name="DateFormat" select="'eee'"/> ? In any case, if you use the body of
> the param tag as a value, I think you shouldn't quote it.
>
> Matthijs
>
> --
> Matthijs Wensveen
> Func. Internet Integration
> W http://www.func.nl
> T +31 20 4230000
> F +31 20 4223500
>
>
It works to output the param to the result.It's just that I can't pass the
xslt parameter as a parameter to my custom class.
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